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6t^2-90t+264=0
a = 6; b = -90; c = +264;
Δ = b2-4ac
Δ = -902-4·6·264
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-42}{2*6}=\frac{48}{12} =4 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+42}{2*6}=\frac{132}{12} =11 $
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